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-4.9x^2+63x+285=0
a = -4.9; b = 63; c = +285;
Δ = b2-4ac
Δ = 632-4·(-4.9)·285
Δ = 9555
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9555}=\sqrt{49*195}=\sqrt{49}*\sqrt{195}=7\sqrt{195}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-7\sqrt{195}}{2*-4.9}=\frac{-63-7\sqrt{195}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+7\sqrt{195}}{2*-4.9}=\frac{-63+7\sqrt{195}}{-9.8} $
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